Monday, 27 August 2012

SYLLABUS OF GATE 2013; MECHANICAL ENGINEERING


Syllabus for Mechanical Engineering (ME)


1) ENGINEERING MATHEMATICS

a) Linear Algebra : Matrix algebra, Systems of linear equations, Eigen values and eigen vectors.

b) Calculus : Functions of single variable, Limit, continuity and differentiability, Mean value theorems, Evaluation of definite and improper integrals, Partial derivatives, Total derivative, Maxima and minima, Gradient, Divergence and Curl, Vector identities, Directional derivatives, Line, Surface and Volume integrals,Stokes, Gauss and Green’s theorems.

c) Differential equations : First order equations (linear and nonlinear), Higher order linear differential equations with constant coefficients, Cauchy’s and Euler’s equations, Initial and boundary value problems, Laplace transforms, Solutions of one dimensional heat and wave equations and Laplace equation.

d) Complex variables : Analytic functions, Cauchy’s integral theorem, Taylor and Laurent series.

e) Probability and Statistics : Definitions of probability and sampling theorems, Conditional probability, Mean, median, mode and standard deviation, Random variables, Poisson,Normal and Binomial distributions.

f) Numerical Methods : Numerical solutions of linear and non-linear algebraic equations Integration bytrapezoidal and Simpson’s rule, single and multi-step methods for differential equations.


2) APPLIED MECHANICS AND DESIGN

a) Engineering Mechanics: Free body diagrams and equilibrium; trusses and frames; virtual work; kinematics and dynamics of particles and of rigid bodies in plane motion, including impulse and momentum (linear and angular) and energy formulations; impact.

b) Strength of Materials: Stress and strain, stress-strain relationship and elastic constants, Mohr’s circle for plane stress and plane strain, thin cylinders; shear force and bending moment diagrams; bending and shear stresses; deflection of beams; torsion of circular shafts; Euler’s theory of columns; strain energy methods; thermal stresses.

c) Theory of Machines: Displacement,velocity and acceleration analysis of plane mechanisms; dynamic analysis of slider-crank mechanism; gear trains; flywheels.

d) Vibrations: Free and forced vibration of single degree of freedom systems; effect of damping; vibration isolation; resonance, critical speeds of shafts.

e) Design: Design for static and dynamic loading; failure theories; fatigue strength and the S-N diagram; principles of the design of machine elements such as bolted, riveted and welded joints, shafts, spur gears, rolling and sliding contact bearings, brakes and clutches.


3) FLUID MECHANICS AND THERMAL SCIENCES

a) Fluid Mechanics: Fluid properties; fluid statics, manometry, buoyancy; control-volume analysis of mass, momentum and energy; fluid acceleration; differential equations of continuity and momentum; Bernoulli’s equation; viscous flow of incompressible fluids; boundary layer; elementary turbulent flow; flow through pipes,head losses in pipes, bends etc.

b) Heat-Transfer: Modes of heat transfer; one dimensional heat conduction, resistance concept, electrical analogy, unsteady heat conduction, fins; dimensionless parameters in free and forced convective heat transfer, various correlations for heat transfer in flow over flat plates and through pipes; thermal boundary layer; effect of turbulence; radiative heattransfer, black and grey surfaces, shape factors, network analysis; heat exchanger performance, LMTD and NTU methods.

c) Thermodynamics: Zeroth, First and Second laws of thermodynamics; thermodynamic system and processes; Carnot cycle.irreversibility and availability; behaviour of ideal andreal gases, properties of pure substances, calculation of work and heat in ideal processes; analysis of thermodynamic cycles related to energy conversion.

d) Applications: Power Engineering : Steam Tables, Rankine, Brayton cycles with regeneration and reheat. I.C. Engines : air-standard Otto, Diesel cycles.

e) Refrigeration and air-conditioning: Vapour refrigeration cycle, heat pumps, gas refrigeration, Reverse Brayton cycle;

f) Moist air: psychrometric chart, basic psychrometric processes.

g) Turbo-machinery: Pelton-wheel, Francis and Kaplan turbines— impulse and reaction principles, velocity diagrams.


4) MANUFACTURING AND INDUSTRIAL ENGINEERING

a) Engineering Materials: Structure and properties of engineering materials, heat treatment, stress-strain diagrams for engineering materials.

b) Metal Casting: Design of patterns, moulds and cores; solidification and cooling; riser and gating design, design considerations.

c) Forming: Plastic deformation and yield criteria; fundamentals of hot and cold working processes; load estimation for bulk (forging, rolling, extrusion, drawing) and sheet (shearing, deep drawing, bending) metal forming processes;principles of powder metallurgy.

d) Joining: Physics of welding, brazing and soldering; adhesive bonding; design considerations in welding.

e) Machining and Machine Tool Operations: Mechanics of machining, single and multi-point cutting tools, tool geometry and materials, tool life and wear; economics of machining; principlesof non-traditional machining processes; principles of work holding, principles of design of jigs and fixtures

f) Metrology and Inspection: Limits, fits and tolerances; linear and angular measurements; comparators; gauge design; interferometry; form and finish measurement; alignment and testing methods; tolerance analysis in manufacturing and assembly.

g) Computer Integrated Manufacturing: Basic concepts of CAD/CAM and their integration tools.

h) Production Planning and Control: Forecasting models, aggregate production planning, scheduling, materials requirement planning.

i) Inventory Control: Deterministic and probabilistic models; safety stock inventory control systems.

j) Operations Research: Linear programming, simplex and duplex method, transportation, assignment, network flow models, simple queuing models, PERT and CPM.

Thursday, 23 August 2012

CONCEPTS OF BASIC THERMODYNAMICS


¤ Introduction:

The most of general sense of thermodynamics is the study of energy and its relationship to the properties of matter. All activities in nature involve some interaction between energy and matter. Thermodynamics is a science that governs the following:

  • (i) Energy and its transformation
  • (ii) Feasibility of a process involving transformation of energy
  • (iii) Feasibility of a process involving transfer of energy
  • (iv) Equilibrium processes

More specifically, thermodynamics deals with energy conversion, energy exchange and the direction of exchange.

¤ Areas of Application of Thermodynamics:

All natural processes are governed by the principles of thermodynamics. However, the following engineering devices are typically designed based on the principles of thermodynamics.

Automotive engines, Turbines, Compressors, Pumps, Fossil and Nuclear Power Plants, Propulsion systems for the Aircrafts, Separation and Liquefaction Plant, Refrigeration, Air-conditioning and Heating Devices.

The principles of thermodynamics are summarized in the form of a set of axioms. These axioms are known as four thermodynamic laws:

  • Zeroth law of thermodynamics,
  • First law of thermodynamics,
  • Second law of thermodynamics, and
  • Third law of thermodynamics.

The Zeroth Law deals with thermal equilibrium and provides a means for measuring temperatures.

The First Law deals with the conservation of energy and introduces the concept of internal energy.

The Second Law of thermodynamics provides with the guidelines on the conversion of internal energy of matter into work. It also introduces the concept of entropy.

The Third Law of thermodynamics defines the absolute zero of entropy. The entropy of a pure crystalline substance at absolute zero temperature is zero.


¤ Different Approaches in the Study of Thermodynamics:

There are two ways through which the subject of thermodynamics can be studied


  • Macroscopic Approach
  • Microscopic Approach


¤ Macroscopic Approach:

Consider a certain amount of gas in a cylindrical container. The volume (V) can be measured by measuring the diameter and the height of the cylinder. The pressure (P) of the gas can be measured by a pressure gauge. The temperature (T) of the gas can be measured using a thermometer. The state of the gas can be specified by the measured P, V and T . The values of these variables are space averaged characteristics of the properties of the gas under consideration. In classical thermodynamics, we often use this macroscopic approach. The macroscopic approach has the following features.

  • The structure of the matter is not considered.
  • A few variables are used to describe the state of the matter under consideration. The values of these variables are measurable following the available techniques of experimental physics.



¤ Microscopic Approach:

On the other hand, the gas can be considered as assemblage of a large number of particles each of which moves randomly with independent velocity. The state of each particle can be specified in terms of position coordinates ( xi , yi , zi ) and the momentum components ( pxi , pyi , pzi ). If we consider a gas occupying a volume of 1 cm3 at ambient temperature and pressure, the number of particles present in it is of the order of 1020. The same number of position coordinates and momentum components are needed to specify the state of the gas. The microscopic approach can be summarized as:


  • A knowledge of the molecular structure of matter under consideration is essential.
  • A large number of variables are needed for a complete specification of the state of the matter.



¤ Zeroth Law of Thermodynamics: 

This is one of the most fundamental laws of thermodynamics. It is the basis of temperature and heat transfer between two systems. Suppose we take three thermodynamic system named System A, System B and System C. Now let that system A is in thermal equilibrium with system B. By thermal equilibrium we mean that there is no heat transfer between system A and system B when they are brought in contact with each other. Now, suppose system A is in thermal equilibrium with system C too and there is no contact between system B and system C. It implies that although system B and C are isolated from each other, they will remain at thermal equilibrium to each other. It means that there will be no heat transfer between system B and C, when they are brought in contact with each other. This is called the Zeroth Law of thermodynamics.


¤ Basis of Temperature: 

When two bodies are kept at contact with each other and if there is no heat transfer between them we say that their body temperatures are same. It means that temperature is the property of a system which decides whether there will be any heat transfer between two different bodies. Heat transfer always occur from a higher temperature body to a lower temperature body. Further whenever there is any heat inflow to a body, it raises its temperature and conversely, if heat outflow occurs from a system it lowers its temperature.

Suppose we take two bodies one of which is at higher temperature than the other. Now when we bring the bodies at contact, heat will be transformed from a higher temperature body to that of lower temperature. Then what will be its effect, we may ask as a result of this heat transfer? Is this heat transfer a perpetual process? Our common life experiences tell us that it will not be the case. Although, at first heat transfer will take place, but its amount will be gradually decreased and after some time, a situation will come when there will be no heat transfer between the bodies or the bodies will come to a state of thermal equilibrium with each other. So, what is the reason for that? Can we justify the situation?

Yes, we can justify it as the hotter body releases heat to the colder body, the temperature of the hotter body decreases where as the temperature of the colder body increases and after sufficient time both the bodies will have equal temperature and a state of thermal equilibrium will be achieved.


¤ Temperature Measurement: 

We know the temperature of a body can be measured with a thermometer. How can we actually calculate the temperature of a body with the help of thermodynamics?


¤ Thermometer:

A thermometer is a temperature measuring instrument. It is made of a thin capillary glass tube, one end is closed and the other end is fitted with metallic bulb full of mercury. The mercury is in thermal equilibrium with the metallic bulb. Therefore, the temperature of the mercury is equal to the temperature of the metallic bulb. 
Mercury has a good coefficient of volume expansion and it means that as the temperature of the mercury increases, its volume increases too and as a result mercury column inside the capillary rises up. 

The capillary tube has been graduated with the help of calibrating with standard temperature sources. Therefore, the temperature of the mercury can be measured from the height of mercury column as the tube is finely graduated. 

Whenever we want to measure the temperature of a body, we kept the body in contact with the metallic bulb of the thermometer. When thermal equilibrium is established between the body and the metallic bulb of the thermoneter, the temperature of both the body will be equal again the metallic bulb is in thermal equilibrium with mercury then the temperature of the mercury will be equal to the temperature of the metallic bulb and the temperature of the object.


As we can measure the temperature of the mercury from the column height, hence we can also determine the temperature of the object as they are equal to each other.

DISCUSSION:
Microscopic basis of temperature and pressure:
Here we shall try to discuss the basis of temperature and pressure only qualitatively, without any mathematical expression. 






.....................contact me at email: subhankarkarma@gmail.com for more notes

Tuesday, 21 August 2012

BASICS OF THERMODYNAMICS


Thermodynamic Systems: 


If we want to analyze movement of energy over space, then we must define the space that would be used for the observation, we would call it as a System, separated from the adjoining space that is known as "Surroundings", by a boundary that may be real or may be virtual depending upon the nature of the observation. The boundary is called as System Boundary. So, we shall now define a system properly.


A thermodynamics system refers to a three dimensional space occupied by a certain amount of matter known as ''Working Substance'', and it is the space under consideration. It must be bounded by an arbitrary surface which may be real or imaginary, may be at rest or in motion as well as it may change its size and shape. All thermodynamic systems contain three basic elements:


System boundary: The imaginary surface that bounds the system.
System volume: The volume within the imaginary surface.
The surroundings: The surroundings are everything external to the system.


So we get a space of certain volume where Energy Transfer (movement of energy) is going on, what may or may not be real, and distinct, it may be virtual (in case of flow system ), again if real boundary exists, then it may be fixed (rigid boundary like constant volume system) or may be flexible (like cylinder-piston assembly). For a certain experiment the system and surroundings together is called Universe.

The interface between the system and surroundings is called as "System boundary", which may be real and distinct in some cases where as some of them are virtual, but it may be real, solid and distinct. If the air in this room is the system, the floor, ceiling and walls constitutes real boundaries. The plane at the open doorway constitutes an imaginary boundary.



Classification of Thermodynamic Systems:

Systems can be classified as being (i) closed, (ii) open, or (iii) isolated.


(i) Closed System:

A thermodynamic system may exchange mass and energy with its surroundings. There are systems which allow only energy transfer with surroundings in the form of either heat transfer or work transfer or both heat and work transfer between a system and its surroundings. In these types of system, any sorts of mass transfer between the system and its surroundings are prohibited. These types of systems are classified as closed system. Examples of closed thermodynamic systems include a fluid being compressed by a piston inside a cylinder, a bomb calorimeter. In a closed system although energy content may vary over a period of time, but the system will always contain the same amount of matter.






(ii) Open System or Control Volume: 

An open system is a region in space defined by a boundary across which matter may flow in addition to work and heat exchange between the system and the surroundings. So, in an open system, the boundaries must have one or more opening through which mass transfer may take place in addition to work and heat transfer. Most of the engineering devices are examples of open system. Some examples are (a) a gas expanding from a container through a nozzle, (b) steam flowing through a turbine, and (c) water entering a boiler and leaving as steam. The boundary of an open system may be real or imaginary and it is called as control surface. The space inside an open system is called as control volume.





(iii) Isolated System:  

In an isolated system, there is no interaction between a system and its surroundings. Hence, the quantities of mass and energy in these types of system doesn’t change with time or we can say mass and energy remain constant in an isolated system. If there is no change in energy of a system, it indicates that there is neither any kind of heat transfer nor any kind of work transfer.  Our universe as a whole can be regarded as an isolated system.



Property, Equilibrium and State: 

A property is any measurable characteristic of a system. The common properties include: 

pressure (P)
temperature (T)
volume (V)
velocity (v)
mass (m)
enthalpy (H)
entropy (S)

Properties can be intensive or extensive. Intensive properties are those whose values are independent of the mass possessed by the system, such as pressure, temperature, and velocity. Extensive properties are those whose values are dependent of the mass possessed by the system, such as volume, enthalpy, and entropy. 

Extensive properties are denoted by uppercase letters, such as volume (V), enthalpy (H) and entropy (S). Per unit mass of extensive properties are called specific properties and denoted by lowercase letters. For example, specific volume v = V/m, specific enthalpy h = H/m and specific entropy s = S/m 


*Note that work and heat are not properties. They are dependent of the process from one state to another state.

When the properties of a system are assumed constant from point to point and there is no change over time, the system is in a thermodynamic equilibrium.

The state of a system is its condition as described by giving values to its properties at a particular instant. For example, gas is in a tank. At state 1, its mass is 2 kg, temperature is 160°C, and volume is 0.1 m3. At state 2, its mass is 1 kg, temperature is 80°C, and volume is 0.2  m3..

A system is said to be at steady state if none of its properties changes with time.


State:

It is the condition of a system as defined by the values of all its properties. It gives a complete description of the system. Any operation in which one or more properties of a system change is called a change of state.


Phase:

It is a quantity of mass that is homogeneous throughout in chemical composition and physical structure. Examples of phase are solid, liquid, vapour, gas. Phase consisting of more than one phase is known as heterogenous system, where as if it consists of only one phase, it is called as homogenous system.



Process, Path and Cycle: 

The changes that a system undergoes from one equilibrium state to another are called a process. The series of states through which a system passes during a process is called path.

In thermodynamics the concept of quasi-equilibrium processes is used. It is a sufficiently slow process that allows the system to adjust itself internally so that its properties in one part of the system do not change any faster than those at other parts.

When a system in a given initial state experiences a series of quasi-equilibrium processes and returns to the initial state, the system undergoes a cycle. For example, the piston of car engine undergoes Intake stroke, Compression stroke, Combustion stroke, Exhaust stroke and goes back to Intake again. It is a cycle.


Quasi-static Processes:

Although the processes can be restrained or unrestrained, in practical purpose we need restrained processes.
A quasi-static process is one in which,
The deviation from thermodynamic equilibrium is infinitesimal.
All states of the system passes through are equilibrium states.

In a cylinder-piston assembly, several small weights are placed on the piston as shown in the figure. If we remove a weight, the pressure on the enclosed gas will be reduced by an infinitesimal amount. If we remove these weights one by one very slowly, then the pressure on the gas will be reduced by very small amount very slowly. Every time we remove a weight, the equilibrium state will be changed to a new equilibrium state at a very slow rate, such that the system will be appeared at a static condition as the change is infinitesimally small and the rate of change is also very small. The path of the change will be a series of quasi-equilibrium states. These types of processes are known as quasi-static processes.  


Equilibrium States:

A system is said to be in an equilibrium state if its properties will not be changed without some perceivable effect in the surroundings.
Equilibrium generally requires all properties to be uniform throughout the system.
There are mechanical, thermal, phase, and chemical equilibrium.

Nature has a preferred way of directing changes. As examples, we can say,
Water flows from a higher to a lower level
Electricity flows from a higher potential to a lower one
Heat flows from a body at higher temperature to the one at a lower temperature
Momentum transfer occurs from a point of higher pressure to a lower one.
Mass transfer occurs from higher concentration to a lower one


Equilibrium state will be achieved when there will not be any change of the values of the properties of a system. Neither the system will exchange 
Heat Energy nor any Work exchange nor any kind of mass exchange with its surroundings. There are mainly three kind of Equilibrium and they are as follows.

* Thermal Equilibrium
* Mechanical Equilibrium
* Chemical Equilibrium


Thermal Equilibrium: 

When two bodies are in contact, there will be heat exchange between the bodies if and only there exists a temperature difference (ΔT) between the bodies.

Due to the temperature difference between the bodies, heat will flow from the high temperature body to the low temperature body. 

As a result of this heat transfer, the temperature of the hot body will be decreased and the temperature of the cold body will be increased.

When the temperature of both the bodies becomes equal to each others, the flow of heat stops. This equilibrium condition is known as the Thermal Equilibrium. 


Mechanical Eqiilibrium : 

If there exists a pressure gradient (ΔP) inside a system, between two systems or between a system and its surroundings, then the interface surface will experience a net force not equal to zero and due to which work transfer will happen where the system having higher pressure will do work against the lower pressure system. 

Due to this work transfer, pressure of the high pressure system will be decreased as energy has flown out of the system. On the other hand, the pressure in the low pressure system will be increased. When the pressure becomes equal in both sides, the work energy flow will be stopped and this state is known as the state of Mechanical Equilibrium.;

Chemical Equilibrium:

If there exists a chemical potential (Δμ) within the components of the system or between the system and surroundings, then there will be a spontaneous chemical reaction which will try to neutralize the chemical potential, after sometimes when the chemical potential becomes zero, the reaction stops and then there will not be any more changes in chemical properties of the system. This condition is called Chemical Equilibrium.

When a system attains thermal, mechanical and chemical equilibrium simultaneously, the state of the system is called in a "THERMODYNAMIC EQUILIBRIUM".




Sunday, 12 August 2012

The Heart of the Machine: A Complete Guide to Internal Combustion Engines (ICE)

The Heart of the Machine: A Complete Guide to Internal Combustion Engines (ICE)

⚡ What is an Internal Combustion (IC) Engine?

At its core, an Internal Combustion Engine is a precision machine designed to transform chemical energy into mechanical power. Unlike external combustion systems (like old steam trains), the "magic" happens entirely inside the engine's cylinders.

The Process:

  1. Combustion: A high-energy fuel is mixed with an oxidizer (usually atmospheric air) inside a sealed chamber.

  2. Expansion: This mixture is ignited, creating a controlled explosion that generates extreme heat and high-pressure gases.

  3. Work: These gases expand rapidly, driving a piston or turbine. This linear movement is then converted into the rotational force (torque) that turns wheels, propellers, or generators.




    🔥 The Two Modes of Combustion

    Not all engines "burn" fuel the same way. In modern engineering, we categorize IC engines based on how the combustion flow is managed:

    1. Intermittent Combustion (The "Pulse")

    This is the heart of the automotive world. In these engines, combustion happens in distinct, rapid cycles.

    • Piston Engines: Found in everything from motorcycles to heavy-duty trucks. These use a Four-Stroke or Two-Stroke cycle to capture energy in "gulps."

    • Rotary (Wankel): A unique design that uses a triangular rotor instead of pistons to achieve the same intermittent power delivery.

    2. Continuous Combustion (The "Flow")

    Instead of separate cycles, these engines maintain a constant, steady flame. This allows for massive power output in a compact frame.

    • Gas Turbines: The primary power source for jet aircraft and large-scale power plants.

    • Jet & Rocket Engines: Engineered for extreme thrust, these systems process air and fuel in a non-stop stream to propel vehicles at supersonic speeds.


    Quick Tip for Students: The main difference lies in how the energy is delivered. Intermittent combustion is like a series of rapid hammer strikes, while continuous combustion is like a steady, powerful push.


🚀 Uses & Applications: From Micro-Tools to Massive Machines

The versatility of the IC engine comes from its incredible power-to-weight ratio. Because they don't require massive external boilers, they are the "go-to" for anything that needs to move fast or stay portable.

  • Personal & Commercial Transport: The backbone of global logistics—powering everything from your daily commuter car and high-performance motorcycles to heavy-duty freight trucks and transcontinental buses.

  • Aerospace & Marine: While massive Gas Turbines propel commercial jets and naval destroyers, smaller Piston Engines remain the standard for light aircraft and motorboats.

  • Industrial & Emergency Power: Used extensively in construction machinery (excavators, cranes) and as critical backup generators for hospitals and data centers when the grid fails.

  • Portable Equipment: Because of their energy density, they power essential tools like chainsaws, lawnmowers, and high-pressure pumps where battery tech isn't yet practical.


🧪 The Combustion Mechanism: The Science of the "Bang"

Combustion is an exothermic chemical reaction—a fancy way of saying it releases a massive amount of energy in the form of heat. In an IC engine, this is a highly controlled "explosion" managed by three key players:

1. The Reactants

To get power, the engine needs a precise mix of Fuel (hydrocarbons like gasoline or diesel) and an Oxidizer (oxygen from the intake air).

Modern Pro-Tip: Some high-performance setups inject Nitrous Oxide ($N_2O$) to provide extra oxygen, allowing more fuel to burn and creating a massive power surge.

2. The Chemistry

When ignition occurs, the chemical bonds in the fuel break and reform, producing:

  • Extreme Heat: Expanding the gases at lightning speed.

  • Byproducts: Water vapor ($H_2O$) and Carbon Dioxide ($CO_2$).

  • Pressure: The real hero. It’s this pressure that physically hammers the piston down to create motion.

3. The Efficiency Factor

The temperature and pressure reached inside the chamber are determined by the Fuel Grade and the Oxygen-to-Fuel ratio. In modern smart engines, sensors adjust this mix thousands of times per second to ensure every drop of fuel is used efficiently with minimal waste.



🆚 IC Engine vs. Steam Engine: The Heavyweight Battle

While both are Heat Engines that convert thermal energy into mechanical work, they operate on entirely different philosophies. Here is how they stack up in the modern era:

At a Glance

Feature Internal Combustion (IC) External Combustion (Steam)
Combustion Site Inside the cylinder. Outside (in a separate boiler).
Starting Time Instant. Turn a key and go. Slow. Needs time to build steam pressure.
Efficiency High ($35\%–40\%+$). More bang for your buck. Low ($10\%–15\%$). Much heat is lost in transit.
Size & Weight Compact & Portable. Ideal for cars. Bulky & Heavy. Requires a boiler and water tank.
Operating Temp Extremely high; requires robust cooling. Lower than IC, but requires high-pressure safety.

🧠 Why the IC Engine Won the 20th Century

  1. The "Start-and-Go" Advantage: A steam engine is like a campfire—you have to build it, wait for it to get hot, and maintain it. An IC engine is like a flashlight—power is available the moment you need it.

  2. Power Density: Because the combustion happens directly on the piston, there is no energy lost moving steam through pipes. This makes IC engines small enough to fit in a lawnmower but powerful enough to move a semi-truck.

  3. Simplified Design: Modern IC engines don't need "stuffing boxes" or massive external pressure vessels. They are self-contained units, making them cheaper to manufacture and easier to fit into aerodynamic vehicle frames.


Study Note: In the modern world, we still use "External Combustion" (Steam Turbines) in nuclear and coal power plants because they are great at constant, massive power. But for anything that moves, the IC Engine is the undisputed champion.


🏗️ The IC Engine Taxonomy: How We Classify Power

Engineering isn't one-size-fits-all. We categorize IC engines based on their "DNA"—from how they breathe to how they ignite.

1. Ignition Method: How the Fire Starts

  • Spark Ignition (SI): The classic petrol engine setup. A spark plug provides the initial "bolt" to ignite the air-fuel mix.

  • Compression Ignition (CI): The Diesel method. Air is squeezed so tightly that the heat alone ignites the fuel upon injection.

2. The Mechanical Cycle

Type Characteristics Best For...
4-Stroke Intake, Compression, Power, Exhaust. Cars, Trucks, and Generators.
2-Stroke Completes a cycle in just two movements. Chainsaws, Jet Skis, and RC Planes.

3. Cylinder Architecture (The Layout)

The way cylinders are arranged affects the engine's balance and size:

  • Inline: Cylinders in a straight row (Simple & reliable).

  • V-Engine: Two rows at an angle (Compact & powerful).

  • Radial: Cylinders arranged like a star (Common in vintage aircraft).

  • Opposed/Flat: Cylinders "punching" away from each other (Low center of gravity).

4. Breathing & Cooling

  • Air-Cooled: Uses fins and airflow (Motorcycles, small tools).

  • Liquid-Cooled: Uses a radiator and coolant (Standard for modern cars).

  • Naturally Aspirated: Breathes atmospheric air normally.

  • Turbo/Supercharged: Uses a "forced induction" pump to cram more air in for massive power gains.


🛠️ The "Smart Engine" Upgrade

In 2026, we add a new category that didn't exist in older textbooks:

The Smart Engine Management System (EMS):

Modern engines are no longer purely mechanical. They are Software-Defined. Using sensors for oxygen, temperature, and throttle position, a central computer (ECU) optimizes the Combustion Mechanism in real-time, reducing emissions while maximizing torque.





📏 The Engine Blueprint: Key Terminology

Think of these as the "dimensions" of power. Understanding these helps you calculate exactly how much work an engine can do.

  • The Bore ($d$): The inner diameter of the cylinder. A larger bore means more room for the Combustion Mechanism to push.

  • The Stroke ($L$): The distance the piston travels between its two extreme points (TDC to BDC).

  • Dead Centers (TDC & BDC): * Top Dead Center (TDC): The "highest" point where the piston stops before heading back down.

    • Bottom Dead Center (BDC): The "lowest" point where the piston stops before heading back up.

  • Swept Volume ($V_s$): The actual volume displaced by the piston as it moves.

    The Formula:

    $$V_s = \frac{\pi \cdot d^2 \cdot L}{4}$$
  • Compression Ratio ($r$): The ratio of the total cylinder volume to the tiny space left at the top (Clearance Volume).

    • Petrol Engines: Usually $5:1$ to $9:1$.

    • Diesel Engines: High-pressure beasts at $14:1$ to $22:1$.


🧩 The Anatomy of an IC Engine

If the Definition of an IC Engine is the "soul," these components are the "body."

🏢 The Core Structure

  • Engine Block: The "foundation" of the engine. It houses the cylinders and, in modern cars, features a "water jacket" for liquid cooling.

  • Cylinder Head: The "cap" that seals the top of the cylinders, housing the valves and spark plugs.

  • Crankcase: The largest cavity that protects the crankshaft and acts as an oil reservoir.

⚙️ The Moving Parts

  • Piston & Rings: The "hammer" that receives the force of combustion. Rings ensure a gas-tight seal so no pressure escapes.

  • Connecting Rod: The bridge that turns the piston's up-and-down "linear" motion into something useful.

  • Crankshaft: The "backbone." It converts that linear push into Rotational Torque to turn your wheels.

  • Camshaft: The "conductor." It ensures the valves open and close with perfect timing.

🌬️ The Support Systems

  • Valves (Intake & Exhaust): The "lungs" of the engine.

  • Spark Plug (SI Engines): The "match" that starts the fire.

  • Fuel Injector: Precision-engineered nozzles that spray fuel into the chamber at high pressure.


💡 Modern Tech Note: The "Smart" Component

The original 2012 post mentions the Carburetor, but today, these are mostly museum pieces. Modern engines use Electronic Fuel Injection (EFI) and Engine Management Systems (EMS)—computers that "think" for the engine to keep it efficient.



OCTANE AND CETANE NUMBERS



Self ignition temperature (SIT) of a fuel is the temperature at which the fuel ignites on its own without spark. If large amount of mixture in an engine cylinder auto ignites, there will be a rapid rise in pressure causing direct blow on engine structure accompanied by thudding sound. This causes vibrations in the engine. The phenomenon is called knocking.

If however, a small pocket of fuel-air mixture auto ignites, pressure waves are generated which travel with the speed of sound across the cylinder. These pressure waves are of such small duration that indicator diagram mechanism fails to record them. These waves interact within themselves and with the cylinder walls, creating characteristics ping sound. The phenomenon is called pinking.

The engine runs rough, overheats and loses efficiency due to knocking and pinking.

The processes of knocking and pinking are related to the nature of the fuel and relative merits of the fuel are decided on the basis of their anti-pinking and anti-knock property. The merit is measured by octane number such that a fuel of high octane number will be liable to less pink or knock as compared to a fuel of low octane number in the same engine. It is important to note that the same fuel will show same tendency to pink or knock in all engines.

Commonly used fuel in SI engines is a mixture of iso-octane and n-heptane. Iso-octane has minimum tendency to knock and this fuel is arbitrarily assigned an octane number of 100 (ON = 100) where as n-heptane has maximum knocking tendency with ON = 0. The octane number of a given fuel is percentage of iso-octane in the mixture of iso-octane and n-heptane. Thus a fuel other than mixture of iso-octane and n-heptane if assigned an ON of 80, it means, it will knock under standard operating condition similar to the mixture of 80% iso-octane and 20% n-heptane.

The tendency to knock in an engine increases with the increase in compression ratio. The highest compression upto which no knocking occurs in a given engine is called highest useful compression ratio (HUCR).

Certain chemical compounds when added to the fuel successfully suppress the knocking tendency. Tetra-ethyl lead [Pb(C2 H5)4] also commonly called TEL and tetra-methyl lead [Pb(CH3)4] also referred to as TML are effective dopes in the automobile fuel to check knocking. They are called as anti-knocking agents. However, because of lead poisoning effects TEL and TML are not being used now-a-days. In stead, some organic auto knocking agents have been developed to check the undesirable effects like knocking.

In CI engine air alone is compressed to a compression ratio of 15 to 20 (commonly). The fuel is injected under a pressure of 120 to 210 bars about 20° to 35° before TDC. As the fuel in the engine starts to evaporate the pressure in the cylinder drops and it delays the ignition process by a small amount. The time between beginning of injection and the beginning of combustion is known as the delay period which consists of time for atomization, vapourization and mixing along with time of chemical reaction prior to auto-ignition. The combustion of fuel continues in the expansion and is called after burning. Increased delay period causes accumulation of atomized fuel in the combustion chamber and as the pressure and temperature continue to rise at one instant, the bulk of fuel auto-ignites. This would result in high forces on the structure of the engine causing vibration and rough running.

The CI engine fuel rating is based on ignition delay and is measured in terms of cetane number. Cetane fuel [C16 H34] has very low delay period and is arbitrarily assigned a cetane number of 100. Another fuel a α-methyl-napthalene [C11 H10] has poor ignition quality and is assigned zero cetane number. The volume percentage of cetane in a mixture of cetane and a-methyl naphthalene is the cetane number of the fuel that produces same delay period as the mixture under specified test conditions. Additives such as methyl nitrate, ethyl thio-nitrate and amyl nitrate increase cetane number of a fuel respectively by 13.5%, 10% and 9% if added to the extent of 0.5%.

Thursday, 9 August 2012

MOCK CLASS TEST: THERMODYNAMICS
Sub: Code: EME-303; Mahamaya Technical University

Time: 2 hrs                                                                                                   Maximum Marks: 50 

Attempt all the questions: 

SECTION A: 

1) Attempt the following questions:                                                                        (5 x 2 = 10) 

a) Define system, surroundings and universe. 

b) Distinguish between Heat pump and Refrigerator. 

c) What is Exergy and Anergy? 

d) Explain the law of degradation of energy. 

e) What is triple point of water? 

SECTION B: 


2) Attempt any three questions:                                                                               (3 x 5 = 15) 

a) Distinguish between macroscopic and microscopic approaches of thermodynamics. 

b) Discuss the neccessity of 2nd law of thermodynamics. 

c) 2 kg of a gas at 10 bar expands adiabatically and reversibly till its pressure drops to 5 bar. During the process 120 kJ of non-flow work is done by the system and the temperature drops from 377°C centigrade to 257°C. Calculate the value of the index of expansion and the characteristics gas constants. 

d) Steam at a pressure of 4 bar absolute and having dryness fraction 0.8, is heated at constant volume to a pressure of 8 bar absolute. Find the final temperature of the steam. Also, find the total heat absorbed by 1 kg of steam. 

e) 2 kg of air at NTP is heated at constant volume untill the pressure becomes 6 bar. Find the change of entropy of the system. 

SECTION C: 

Attempt part (a) or part (b) of the following questions                                                 (5 x 5 = 25) 

3) (a) Explain the thermodynamic equilibrium and quasi-static process. 

(b) Prove the equivalence of Kelvin-Planck statement and Clausius statement. 

4) (a) A steam turbine developing 110 kW is supplied steam at 17.5 bar with an internal energy of 2600 kJ/min, specific volume = 15.5 m³/kg and velocity of 275 m/s. Heat loss from the steam turbine  37.6 kJ/kg. Neglecting the changes in potential energy, determine the steam flow rate in kg/hr. 

(b) A reversible engine takes 2400 kJ/min from a reservoir at 750 K develops 400 kJ/min of work during cycle. The engine rejects heat at two reservoir at 650 K and 550 K. Find the heat rejected to each sink. 

5) (a) Explain the causes of internal and external irreversibility. 

(b) Explain the importance of Gibb's function and Gibb's free energy. 

6) (a) 5 kg steam at pressure 8 bar and temperature 300°C is adiabatically mixed with 4 kg steam at 6 bar and 250°C. Find the final condition of the mixture. Also find the change in entropy. 

(b) Hot steam is flowing through a perfectly adiabatic pipe. At point A the temperature of the steam is 250°C and pressure is 4 bar, while at the point B, its temperature is 275°C and pressure is 3.5 bar. Find the direction of the flow. 

7) (a) 5 kg of Oxygen is enclosed within a vessel of 0.05 m³ at a temperature 200°C, is being supplied 120 kJ of energy through heating. Find the final pressure and temperature. 

(b) One kg of an ideal gas is heated from 18.3°C to 93.4°C. Assuming R = 287 J/kg-K and  γ  = 1.18 for the gas. Find out (i) specific heats, (ii) change in internal energy, and (iii) change in enthalpy and entropy.





Monday, 6 August 2012

KINEMATICS ANALYSIS : MOVING BODIES......


KINEMATICS ANALYSIS: MOVING BODIES......
Mechanics, physics, mechanical engineering

What makes a body moving?

OBSERVATION ONE:

"From our perception, we can say, a body moves if we apply either a push or a pull on the body. There are several  instances, when after applying push or pull, the body still doesn't move. What is the exact reason behind this?"

OBSERVATION TWO:

"Almost to apply a push or pull on a body, a physical contact is needed, with out any physical contact it is not possible to exert push/pull on a body, although there are exceptions too.

(i) We know on every material body existing on earth experience a downward pull towards the center of Earth and to exert this pull, the object and the earth don't need any physical contact. This phenomena is aptly named as the 'Force of Gravity.'

(ii) The second option is Magnet. A magnet can pull as well as push another magnet from a distance with out any physical contact.

(iii) When we place a charged particle near another charged particle, we watch the particles can exert push as well as pull without any physical contact. Like a proton repels another proton, ie they exert push on each other. But a proton attracts an electron by pulling each other to come close.

So there are two types of motion. Type one is the example of a Cricket ball going to boundary after being hit by the bat. So, here impact is the driver of the motion.

But an apple falling from a tree is also in motion, but for this no impact is there. In fact the attraction between the apple and the earth is responsible for the motion. By attraction, it means the tendency of going closer in two objects. Here motion of apple occurs without being hit.


LINEAR MOTION:

We know that Force is a kind of physical quantity having both magnitude as well as direction. So, force is a vector quantity. We also know that applying triangle's law or parallelogram law of forces addition, we can add two forces to get an equivalent force which is known Resultant force.

So, application of force on an object brings a change in position of the object. This change is position is called displacement. An object in a coordinate system has a position vector to define the position vector. Any change of position will bring change in its position vector.

Suppose in a coordinate system we have an object at a position vector (r). Let after a time interval of (dt), the object changes its position by an amount (dr). Hence, the rate of change of position will be (dr)/(dt). Rate of change of position

means the change of position in unit time. Rate of change of position is called velocity of the object. It is denoted by (v).

Hence, (v) = (dr)/(dt).
The unit of velocity is m/s in SI units and cm/s in cgs system. The most popular unit is km/hr.

A velocity may change, it may change in direction or it may change in magnitude. Suppose, we have an object moving with a velocity (v) at any instant. Suppose after an interval of time (dt), its new velocity becomes (v + dv), where (dv) is the change in velocity. Hence (dv)/(dt) will be the rate of change of velocity and it indicates the change of velocity per unit time. This physical quantity is called acceleration. Negative acceleration which is rate of decrease in velocity is called retardation or deacceleration too.

Acceleration may be changed; the rate of change of acceleration is called impulse. Like when a bat touches a moving ball, it has an impact and this changes its acceleration due to this magnitude and direction of the ball changes. If a large magnitude of force act on a body for a very short period of time, it is called impulse.

Free falling under the forces of gravity is a case of constant acceleration and that is denoted by (g) and it is equal to g = 9.81  m/s ² .

THREE EQUATIONS OF MOTION

These three equations are valid only in the case of constant acceleration. Every particle falling under the gravity will satisfy these equations.

We know (dv)/(dt) = a,
hence, (dv) = a(dt) or by integrating both side from initial state t = 0; v = u to final t = t; v = v,
we get,
v - u = a(t - 0) or v = u + at

Again, a = (dv)/(dt)
a = {(dv)/(dx)}.{(dx)/(dt)}
a = v.(dv)/(dx)
hence, v.dv = a.dx
Integrating both sides from initial v= u, x = 0 to final v = v, x = s
we get,
v² - u² = 2 a (s - 0)
v² - u² = 2as

From the defination of velocity, we get
v = (dx)/(dt)
but, v = u + at
hence,
u + at = (dx)/(dt)
dx = (u +at). dt
Integrating both sides of the equation from initial condition t = 0, x = 0 and final condition t = t, x = s, we get

(s - 0) = u(t - 0) + (a.t²)/2
s = ut + (at²)/2

Average Velocity = (u + v)/2
= (u + u + at)/2 = u + at/2

Total distance, s = Average Velocity x time

s = (u + at/2) x t
s = ut + (at²)/2

Uses of these equations:

1) Suppose we have a particle travelling with 5 m/s and an acceleration of 1 m/s^2 is applied on the body. What will be the

velocity after a time of 10 s?

Ans: Here, u = 5 m/s, a = 1 m/s ²  and t = 10 s, then

velocity after 10 s,
v = u + at
v = 5 + 1 x 10 = 15 m/s

2) A car moving with a velocity 60 km/hr suddenly applies the brake. As a result, the car comes to a halt after running 50 m

after applying brake. What will the value of retardation? Find the time it needs to come to rest after the application of brake.

Ans: Here, initial velocity u = 60 km/hr = (60 x 1000)/(60 x 60) m/s = 16.67 m/s
final veloity, v = 0 m/s
Total distance travelled s = 50 m
a = (v² - u²)/2s
a = (0 - 16.67²)/(2 x 50)
a = - 2.78 m/s²

again time, t = (v - u)/a
t = (0 - 16.67)/(-2.78)
t = 5.99 s

The Concept of Relative Velocity:

Suppose in a road two car is moving. The faster car at 40 km/hr and the slower car at 30 km/hr in the same direction. Now, if anyone watches the faster car from the slower car, he won't be see it running at 40 km/hr, in stead he will see the velocity at 15 km/hr. When we watch from a moving body or better we say moving reference frame, the velocity of other bodies seem be reduced. Again if we take the same two cars running in opposite directions to each other, the velocity of the each car will be at 55 km/hr as seen from the other. This is due to relative velocity. The relative velocity of a body is the velocity of the body relative to an observer.

Suppose, a car is moving with a velocity Vc and a train is moving with a velocity Vt. Then velocity of car with respect to a person sitting in the train will be Vct = Vc  Vt and velocity of the train to a person in the car will be  Vtc = Vt  Vc  .

3) A train is moving towards east with a velocity 120 km/hr and wind is blowing towards west with a velocity 20 km/hr. What will the velocity of the wind to an observer in the train?

Ans: We shall take towards east direction as positive and towards west direction as negative.
Let the velocity of train is (Vt) and velocity of wind is (Vw)

So,  Vt  = 120 km/hr and
Vw = - 20 km/hr

Vwt =  Vw  - Vt
Vwt = - 20 - 120 = - 140 m/s and it means wind is flowing from west.

4) A car is moving on a horizontal road at 40 km/hr. Suddenly rain started to pour down at a velocity 30 km/hr. Find the

velocity of the rain drops with rest to an observer in the car. Also find the angle with which rain drops would appear to strike the car.

Ans: Let the velocity of the car be Vc = 40 km/hr and rain drop velocity is  Vr = - 30 km/hr. The angle between them is θ = 90°.
(Vrc) = (Vr) - (Vc)
(Vrc)² = (Vr)² + (Vc)² - 2(Vr)(Vc) cos θ
= 30² + 40² + 0
= 2500
(Vrc) = 50 m/s

ANGULAR MOTION:

Suppose a line AB displaces side wise such that A remains at same point, but the other end B comes to new position C. This is an angular displacement. Angles are measured in radian. 1 radian is the angle formed by an arc equals to magnitude of radius (r). A full circle produces 2π.

Suppose, a line of length (r) makes an angular displacement of (dθ) in time (dt). Then the rate of change of angular displacement is given by (dθ)/(dt) and it is called angular velocity, (w). Hence, (w) = (dθ)/(dt).

If we apply torque or moment in the line, the angular velocity will be changed. Let during the time interval, (dt), the change in angular velocity be (dω). The rate of change of angular velocity will (dω)/(dt) and it is called as angular acceleration and denoted as α.

α = (dω)/(dt)
(dω) = α.(dt)
Taking initial value ω = ωₒ, t = 0, to final value ω = ω, t = t and integrating both side, we get,
ω - ωₒ = α.(t - 0)
ω = ωₒ + αt

angular velocity ω = (dθ)/(dt)
ωₒ + αt = (dθ)/(dt)
(ωₒ + αt)(dt) = dθ
Taking initial value θ = 0, t = 0, to final value, θ = θ, t = t, and integrating both side we get,

ωₒ.(t - 0) + (α/2)(t² - 0) = θ - 0

θ = ωₒt + (αt²/2)

α = (dω)/(dt)
= {(dω)/(dθ)}.{(dθ)/(dt)}
α = ω.(dω)/(dθ)
ω.(dω) = α.(dθ)
taking the initial value ω = ωₒ, θ = 0 and final value ω =ω, θ = θ and integrating both sides,
(ω²)/2 - (ωₒ²)/2 = α.(θ - 0)
(ω²) = (ωₒ²) + 2.α.θ



MOTION OF A RIGID BODY

Plane Motion:

A rigid body is said to be in plane motion when all parts of the body move in parallel planes. The plane motion of a rigid body may be classified into several categories like :

1) Translation
2) Rotation
3) General plane motion.

Translation:

Sunday, 5 August 2012

ENGINEERING MECHANICS CLASS TEST: ONE


CLASS TEST: ONE
Time: 1 hr 30 min                                                                                        Max. Marks: 30
                                                                                                                         
1) Answer the following question in brief                                                              2 x 6 = 12   
                                                                 
a)      Distinguish clearly between composition of forces and resolution of forces.
b)      Show that the algebraic sum of the resolved part of a number of forces in a given direction is equal to the resolved part of their resultant in the same direction.
c)      Differentiate between coplanar forces and concurrent forces clearly.
d)     State and explain the laws of transmissibility of forces.
e)      Explain Newton’s third law of motion.
f)       What is a couple? Explain its characteristics.


2) Answer any two of the following questions                                                     6 x 3 = 18

a)      A smooth circular cylinder of radius 1500 mm is lying in a triangular groove, the right side of which makes 20° angle and left side makes 40° angle with horizontal. Find the reaction at each contact if there is no friction and the cylinder weight is 400 N.

                                                                                             
b)      A right circular cylinder of weight 5 kN rests on a smooth inclined plane and is held in position by a cord AC as shown in the figure. Find the tension in the cord if there is a horizontal force of magnitude 1 kN acting at C.





c)      Four forces of magnitude 10 kN, 18 kN, 15 kN and 12 kN are acting along the diagonals and sides of a regular pentagon as shown in the figure. Find the resultant force of the given force system.






d)     Prove that if a body is at equilibrium under three forces, then the forces are concurrent forces.