Concept of the Day

🧪 The Markovnikov’s Rule

$CH_3-CH=CH_2 + HBr$ $ \longrightarrow CH_3-CH(Br)-CH_3$

The Rule: In the addition of a protic acid ($HX$) to an asymmetric alkene, the acid hydrogen ($H$) attaches to the carbon with the greater number of hydrogen atoms, while the halide ($X$) group attaches to the carbon with the greater number of alkyl substituents.

"The rich get richer."

Note: Essential for solving reaction mechanisms in Class 12, JEE, and NEET Prep.

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