Concept of the Day

๐Ÿงช The Markovnikov’s Rule

$CH_3-CH=CH_2 + HBr$ $ \longrightarrow CH_3-CH(Br)-CH_3$

The Rule: In the addition of a protic acid ($HX$) to an asymmetric alkene, the acid hydrogen ($H$) attaches to the carbon with the greater number of hydrogen atoms, while the halide ($X$) group attaches to the carbon with the greater number of alkyl substituents.

"The rich get richer."

Note: Essential for solving reaction mechanisms in Class 12, JEE, and NEET Prep.

Concept of the Day Archive

Motion Worksheet

Worksheet: Equations of Motion

๐Ÿ“˜ Worksheet: Motion (Equations of Motion)

Equations of Motion:

1. v = u + at

2. s = ut + (1/2)at²

3. v² = u² + 2as

๐Ÿ”น Section A: Basic Problems

1. A car starts from rest and accelerates uniformly at 2 m/s² for 5 seconds. Find its final velocity.
2. A body moves with an initial velocity of 10 m/s and acceleration 3 m/s² for 4 seconds. Find the distance travelled.
3. A train slows down from 20 m/s to 10 m/s in 5 seconds. Find its acceleration.
4. A body starts with velocity 5 m/s and covers 50 m under uniform acceleration. Find final velocity.
5. A stone is thrown vertically upward with velocity 20 m/s. Find the time taken to reach maximum height. (Take g = 10 m/s²)

๐Ÿ”น Section B: Moderate Level

6. A car accelerates from 10 m/s to 30 m/s in 10 seconds. Find the distance travelled.
7. A ball is dropped from a height. Find the velocity after 4 seconds. (g = 9.8 m/s²)
8. A particle moving with uniform acceleration travels 40 m in 4 seconds and 80 m in next 4 seconds. Find acceleration.
9. A vehicle moving at 15 m/s comes to rest in 5 seconds. Find distance travelled.
10. A body covers 100 m in 5 seconds with uniform acceleration. If initial velocity is 10 m/s, find acceleration.

๐Ÿ”น Section C: Higher Order Thinking

11. A car starts from rest and covers 200 m in 10 seconds. Find its acceleration and final velocity.
12. A body is projected upward with velocity 30 m/s. Find maximum height reached.
13. A train moving at 72 km/h is brought to rest in 10 seconds. Find retardation and distance travelled.
14. A particle starts from rest and travels 100 m in 10 seconds. Find its velocity at the end.
15. A stone is thrown downward with velocity 5 m/s from a height. Find velocity after 3 seconds.

๐Ÿ”น Section D: Assertion–Reason

16. Assertion: A body moving with constant velocity has zero acceleration.
Reason: Acceleration depends on change in velocity.
17. Assertion: Distance travelled in equal intervals increases in uniformly accelerated motion.
Reason: Velocity increases with time.

๐Ÿ”น Section E: Case Study

18. A car starts from rest and accelerates at 4 m/s² for 5 seconds, then moves at constant velocity for next 5 seconds. a) Find velocity after 5 seconds
b) Distance covered in first 5 seconds
c) Total distance in 10 seconds