Concept of the Day

๐Ÿงช The Markovnikov’s Rule

$CH_3-CH=CH_2 + HBr$ $ \longrightarrow CH_3-CH(Br)-CH_3$

The Rule: In the addition of a protic acid ($HX$) to an asymmetric alkene, the acid hydrogen ($H$) attaches to the carbon with the greater number of hydrogen atoms, while the halide ($X$) group attaches to the carbon with the greater number of alkyl substituents.

"The rich get richer."

Note: Essential for solving reaction mechanisms in Class 12, JEE, and NEET Prep.

Concept of the Day Archive

Vernier Calipers: Practice Problems and Measurement Techniques

vernier calliper

๐Ÿ”ง What is a Vernier Callipers?

A vernier calipers is a precise measuring instrument used to measure:

  • Length

  • Diameter (internal & external)

  • Depth

It is more accurate than a normal ruler.


⚙️ How Vernier Callipers Measures

It has two scales:

1. Main Scale

  • Fixed scale (like a ruler)

  • Gives measurement in cm or mm

2. Vernier Scale

  • Sliding scale

  • Helps measure very small differences more accurately


๐Ÿง  Working Principle

The idea is simple:

๐Ÿ‘‰ The vernier scale divisions are slightly smaller than the main scale divisions

Because of this:

  • At any position, one line on the vernier scale exactly matches one line on the main scale

  • That matching line tells you the extra fraction to add


๐Ÿ“ How to Take Reading

  1. Note Main Scale Reading (MSR)
    → The value just before the zero of vernier scale

  2. Find Vernier Coincidence (VSR)
    → Which vernier line exactly matches a main scale line

  3. Final Reading Formula

$ \text{Measurement} = \text{MSR} + (\text{VSR} \times \text{Least Count}) $


๐Ÿ“‰ What is Least Count?

๐Ÿ‘‰ Least Count = Smallest measurement the instrument can measure

For vernier calipers:

$\text{Least Count} = \text{Value of 1 Main Scale Division} - \text{Value of 1 Vernier Scale Division}$


๐Ÿ“Š Common Example

  • 1 Main Scale Division (MSD) = 1 mm

  • 10 Vernier divisions = 9 mm

So,

  • 1 Vernier Division = 9/10 = 0.9 mm

$\text{Least Count} = 1 - 0.9 = 0.1 \text{ mm}$


๐ŸŽฏ Final Understanding

  • Main scale gives whole part

  • Vernier scale gives fractional part

  • Least count tells precision


๐Ÿ’ก Easy Analogy

Think of it like:

  • Main scale = whole number

  • Vernier scale = decimal part



JEE Main–level PYQ-style questions on Vernier Callipers (Units & Measurements).


๐Ÿ”ฌ Vernier Callipers –
Practice Questions (JEE Main Level)

Q1. Least Count Concept

A Vernier calipers has 10 divisions on the Vernier scale coinciding with 9 divisions on the main scale. If one main scale division = 1 mm, the least count is:

A. 0.1 mm
B. 0.01 mm
C. 0.2 mm
D. 0.05 mm


Q2. Reading with Zero Error

The main scale reading is 2.3 cm and the 6th Vernier division coincides. Least count = 0.01 cm. Zero error = +0.02 cm.
Find the corrected reading.


Q3. Negative Zero Error

A Vernier calipers shows a zero error of −0.03 cm. The observed reading of a rod is 5.24 cm.
Find the actual length.


Q4. Backlash-Type Concept

While measuring, the Vernier reading fluctuates between 8th and 9th division. Least count = 0.01 cm.
Estimate the uncertainty in measurement.


Q5. Diameter Measurement

The diameter of a sphere is measured as:

Main scale reading = 1.2 cm
Vernier coincidence = 5
Least count = 0.01 cm

Find the volume of the sphere (approx).


Q6. Conversion Trick

A Vernier calipers has least count 0.02 mm. Express it in cm.


Q7. Advanced Coincidence Logic

In a Vernier calipers, 50 Vernier divisions coincide with 49 main scale divisions.
If 1 MSD = 1 mm, find least count.


Q8. Internal vs External Measurement

Which part of Vernier calipers is used to measure:

  1. Internal diameter

  2. Depth

A. Lower jaws, depth rod
B. Upper jaws, depth rod
C. Lower jaws, upper jaws
D. Depth rod, lower jaws


Q9. Error Propagation

If the least count is 0.01 cm, what is the percentage error in measuring a length of 2 cm?


Q10. Trick Question (JEE Style)

A Vernier calipers gives the following readings:

  • MSR = 3.4 cm

  • Vernier coincidence = 7

  • Least count = 0.01 cm

  • Zero error = −0.02 cm

Final reading is:

A. 3.45 cm
B. 3.47 cm
C. 3.49 cm
D. 3.43 cm